2010 AMC 8 Problems/Problem 23
Contents
Problem
Semicircles and pass through the center . What is the ratio of the combined areas of the two semicircles to the area of circle ?
Solution
By the Pythagorean Theorem, the radius of the larger circle turns out to be . Therefore, the area of the larger circle is . Using the coordinate plane given, we find that the radius of each of the two semicircles to be 1. So, the area of the two semicircles is . Finally, the ratio of the combined areas of the two semicircles to the area of circle is .
Solution 2
We first calculate the area of the two semicircles. We can see that the radius is 1, so the area of the two total semi-circles is pi. Using the circle equation, (x-h)^2+(y-k)^2=r^2, we know the centre is (0,0), so the equation becomes x^2+y^2=r^2. We sub in the values that were given to us to find that the radius is sqrt2. Therefore, the area if 2pi. We then find the ratio of them, which is
-CharmaineMa07292010
Video Solution by OmegaLearn
https://youtu.be/abSgjn4Qs34?t=903
~ pi_is_3.14
=Video by MathTalks
Video Solution by WhyMath
~savannahsolver
See Also
2010 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 22 |
Followed by Problem 24 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.