1968 AHSME Problems/Problem 17
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Problem
Let , where
is a positive integer. If
, the set of possible values of
is:
Solution
Because we start with , and the terms
alternate between
and
, there is either one more
than the number of
s (when
is odd), or there are an equal number of
s and
s (when
is even). In the former case,
, and, in the latter case,
. This is only consistent with answer
.
See also
1968 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
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