1959 AHSME Problems/Problem 36

Problem

The base of a triangle is $80$ , and one side of the base angle is $60^\circ$ . The sum of the lengths of the other two sides is $90$ . The shortest side is: $\textbf{(A)}\ 45 \qquad\textbf{(B)}\ 40\qquad\textbf{(C)}\ 36\qquad\textbf{(D)}\ 17\qquad\textbf{(E)}\ 12$

Solution

$\boxed{\textbf{(D) 17}}$

1959 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 35	Followed by Problem 37
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1959 AHSME Problems/Problem 36

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