1957 AHSME Problems/Problem 46

Problem

Two perpendicular chords intersect in a circle. The segments of one chord are $3$ and $4$ ; the segments of the other are $6$ and $2$ . Then the diameter of the circle is:

$\textbf{(A)}\ \sqrt{89}\qquad \textbf{(B)}\ \sqrt{56}\qquad \textbf{(C)}\ \sqrt{61}\qquad \textbf{(D)}\ \sqrt{75}\qquad \textbf{(E)}\ \sqrt{65}$

Solution

$\boxed{\textbf{(E) }\sqrt{65}}$ .

1957 AHSC (Problems • Answer Key • Resources)
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1957 AHSME Problems/Problem 46

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