2011 AMC 8 Problems/Problem 13
Contents
[hide]Problem
Two congruent squares, and
, have side length
. They overlap to form the
by
rectangle
shown. What percent of the area of rectangle
is shaded?
Solution 2
The length of BP is 5. the ratio of the areas is
-Megacleverstarfish15
Solution 3(similar to Solution 1)
To find the overlap length, we do the total length of the squares and subtract (side length of figure).
, so the overlap length is
. To find what percentage of
is shaded, we divide the shaded part by the area of the
, so the percentage is
=
=
=
=
%, so the answer is
.
~NXC
Video Solution
https://www.youtube.com/watch?v=mYn6tNxrWBU
~==SpreadTheMathLove==
Video Solution by WhyMath
See Also
2011 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.