2011 AMC 8 Problems/Problem 18
Contents
Problem
A fair sided die is rolled twice. What is the probability that the first number that comes up is greater than or equal to the second number?
Solution
There are ways to roll the two dice, and 6 of them result in two of the same number. Out of the remaining ways, the number of rolls where the first dice is greater than the second should be the same as the number of rolls where the second dice is greater than the first. In other words, there are ways the first roll can be greater than the second. The probability the first number is greater than or equal to the second number is
Solution 2
If we list out some ways the first dice is greater than the second dice, we might see a pattern.
If dice is , then dice can be or .
If dice is , then dice can be or .
If dice is , then dice can be or .
In the first case, dice had six values it could land on. In the second case, dice had five values it could land on. In the third case, dice had four values it could land on. If we keep going, we would eventually get the pattern as the number of total values dice could land on if it's greater or equal to dice . Since there are ways two dice could land, our answer is , or .
Video Solution by OmegaLearn
https://youtu.be/6xNkyDgIhEE?t=139
~ pi_is_3.14
Video Solution
https://youtu.be/lfrofNkOol0. Soo, DRMS, NM
Video Solution by WhyMath
~savannahsolver
See Also
2011 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
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All AJHSME/AMC 8 Problems and Solutions |
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