2006 Cyprus MO/Lyceum/Problem 23

Problem

Of $21$ students taking Mathematics, Physics and Chemistry, no student takes one subject only. The number of students taking Mathematics and Chemistry only, equals to four times the number taking Mathematics and Physics only. If the number of students taking Physics and Chemistry only equals to three times the number of students taking all three subjects, then the number of students taking all three subjects is

$\mathrm{(A)}\ 0\qquad\mathrm{(B)}\ 5\qquad\mathrm{(C)}\ 2\qquad\mathrm{(D)}\ 4\qquad\mathrm{(E)}\ 1$

Solution

Let $x$ be the number of students in Math and Physics and $y$ be the number of those in all three. Then, $4x$ is the number of students in Math and Chem, and $3y$ is the number of those in Physics and Chem.

Adding, $5x+4y=21$ . We're looking for $y$ , which is $4y\equiv21\equiv1\pmod{5}\Longrightarrow y\equiv4\pmod{5}$ . Since $0\le4y<21$ , the answer is $y=4\ \mathrm{(D)}$ .

2006 Cyprus MO, Lyceum (Problems)
Preceded by Problem 22	Followed by Problem 24
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2006 Cyprus MO/Lyceum/Problem 23

Problem

Solution

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