1998 AHSME Problems/Problem 19
Problem
How many triangles have area 
and vertices at 
and 
for some angle 
?
Solution
The triangle can be seen as having the base on the 
axis and height 
. The length of the base is , thus the height must be 
. The equation 
has 
solutions, one in each quadrant.
![[asy] size(250); defaultpen(0.8); pair A=(-5,0), B=(5,0); dot(A); dot(B); dot((0,0)); pair ip1[] = intersectionpoints( circle((0,0),5), (-6,2) -- (6,2) ); pair ip2[] = intersectionpoints( circle((0,0),5), (-6,-2) -- (6,-2) ); draw ( (-6,0) -- (6,0) ); draw ( A -- ip1[1] -- B, Dotted ); draw ( circle((0,0),5), red ); draw ( (-6,2) -- (6,2), blue ); draw ( (-6,-2) -- (6,-2), blue ); dot(ip1[0]); dot(ip1[1]); dot(ip2[0]); dot(ip2[1]); label("\((-5,0)\)", A, SW ); label("\((5,0)\)", B, SE ); label("\((0,0)\)", (0,0), SE ); label("\(y=2\)", (6,2), N, blue ); label("\(y=-2\)", (6,-2), S, blue ); label("\(y=-2\)", (6,-2), S, blue ); label("\((5\cos\theta,5\sin\theta)\)", 5*dir(-45), SE, red ); [/asy]](http://latex.artofproblemsolving.com/c/6/e/c6e55834b32f7a0ec73bf97c9d22c44ab8d50c75.png)
Visually, the set of points of the form is a circle centered at 
with radius 5. The missing vertex of the triangle must lie on this circle. At the same time, its distance from the axis must be 2. The set of all such points are precisely the lines 
and 
, and each of these lines intersects the circle in two points.
See also
| 1998 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 18 |
Followed by Problem 20 | |
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