1979 AHSME Problems/Problem 29
Problem
For each positive number , let . The minimum value of is
Solution
Let and . Then
By difference of squares,
By the AM-GM inequality, so . Furthermore, when , , so the minimum value of is .
See also
1979 AHSME (Problems • Answer Key • Resources) | ||
Preceded by num-a=28 |
Followed by Problem 30 | |
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