2018 AMC 12B Problems/Problem 5

How many subsets of $\{2,3,4,5,6,7,8,9\}$ contain at least one prime number? $(\text{A}) \indent 128 \qquad (\text{B}) \indent 192 \qquad (\text{C}) \indent 224 \qquad (\text{D}) \indent 240 \qquad (\text{E}) \indent 256$

Solution 1

Since an element of a subset is either in or out, the total number of subsets of the 8 element set is $2^8 = 256$ . However, since we are only concerned about the subsets with at least 1 prime in it, we can use complementary counting to count the subsets without a prime and subtract that from the total. Because there are 4 non-primes, there are $2^8 -2^4 = 240$ subsets with at least 1 prime so the answer is $\Rightarrow (\text{D}) \indent$ (Giraffefun)

$\Large$ See Also

2018 AMC 12B (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
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All AMC 12 Problems and Solutions

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2018 AMC 12B Problems/Problem 5

Solution 1

$\Large$ See Also