1968 AHSME Problems/Problem 26

Problem

Let $S=2+4+6+\cdots +2N$ , where $N$ is the smallest positive integer such that $S>1,000,000$ . Then the sum of the digits of $N$ is:

$\text{(A) } 27\quad \text{(B) } 12\quad \text{(C) } 6\quad \text{(D) } 2\quad \text{(E) } 1$

Note that $S = 2(1+2+3+...+N) = N(N +10)$ . It follows that N = 1000, so the sum of the digits of N is $\fbox{E}$ . (Solution Done By FrostFox)

1968 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 25	Followed by Problem 27
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