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  • ...e triangle can be found using [[trigonometry]] to be of length <math>\frac s2 \cot \frac{180}{n}^{\circ}</math>.
    6 KB (1,181 words) - 22:37, 22 January 2023
  • <cmath>\xi(s)=\frac12s(s-1)\pi^{-s/2}\Gamma\left(\frac s2\right)\zeta(s).</cmath>
    9 KB (1,547 words) - 03:04, 13 January 2021
  • ...is only constrained to positive integer pairs. Please check on "Comment of S2" below to see how to use [[Diophantine equation]] to make a simple deductio ==== Comment on S2 ====
    3 KB (564 words) - 04:47, 4 August 2023
  • so that means s1+s2+s3+s4 must be an even number divisible by 4
    4 KB (618 words) - 00:52, 15 July 2024
  • pair S1=(r1,r1), S2=(r2,r2); dot(S1); dot(S2); dot((3,0));
    2 KB (314 words) - 21:07, 16 January 2020
  • S(s2) - S(s1) = S(s3) - S(s2) 2S(s2) = S(s1) + S(s3)
    1 KB (184 words) - 01:16, 19 November 2023
  • * 10th, 11th and 12th grade students (L1/S2)
    3 KB (498 words) - 08:52, 1 September 2022
  • real s1 = 5, s2 = 7, s3 = 8; // triangle side lengths pair A=(0,0), B = (s1,0), C = intersectionpoints(Circle(A, s3), Circle(B, s2))[0], I = incenter(A,B,C), D = foot(I,B,C), E = foot(I,A,C), F = foot(I,A,B
    55 KB (7,986 words) - 17:04, 20 December 2018
  • pen db = rgb(0,0,0.5); real r = 0.08; pair s1 = (3,0), s2 = 2*s1; ...ft(s2)*unitsquare, db); fill(shift(s2-(0,1+r))*unitsquare, db); fill(shift(s2+(1+r,-1-r))*unitsquare, db);</asy>
    25 KB (4,154 words) - 16:27, 2 September 2011
  • pair S1 = (20, 20), S2 = (-20, 20), S3 = (-20, -20), S4 = (20, -20); pair M1 = (S1+S2)/2, M2 = (S2+S3)/2, M3=(S3+S4)/2, M4=(S4+S1)/2;
    7 KB (1,228 words) - 12:16, 13 March 2020
  • pair S1 = (20, 20), S2 = (-20, 20), S3 = (-20, -20), S4 = (20, -20); pair M1 = (S1+S2)/2, M2 = (S2+S3)/2, M3=(S3+S4)/2, M4=(S4+S1)/2;
    2 KB (362 words) - 16:34, 29 February 2020