Difference between revisions of "1950 AHSME Problems/Problem 12"

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==Solution==
 
==Solution==
  
The exterior angles of all convex polygons add up to <math>360^\circ,</math> so the sum <math>\boxed{\mathrm{(C)}\text{ remains constant}.}</math>
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By the Exterior Angles Theorem, the exterior angles of all convex polygons add up to <math>360^\circ,</math> so the sum <math>\boxed{\mathrm{(C)}\text{ remains constant}.}</math>
  
 
==See Also==
 
==See Also==
  
{{AHSME box|year=1950|num-b=11|num-a=13}}
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{{AHSME 50p box|year=1950|num-b=11|num-a=13}}
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[[Category:Introductory Geometry Problems]]
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{{MAA Notice}}

Latest revision as of 17:40, 27 February 2016

Problem

As the number of sides of a polygon increases from $3$ to $n$, the sum of the exterior angles formed by extending each side in succession:

$\textbf{(A)}\ \text{Increases}\qquad\textbf{(B)}\ \text{Decreases}\qquad\textbf{(C)}\ \text{Remains constant}\qquad\textbf{(D)}\ \text{Cannot be predicted}\qquad\\ \textbf{(E)}\ \text{Becomes }(n-3)\text{ straight angles}$

Solution

By the Exterior Angles Theorem, the exterior angles of all convex polygons add up to $360^\circ,$ so the sum $\boxed{\mathrm{(C)}\text{ remains constant}.}$

See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 11
Followed by
Problem 13
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All AHSME Problems and Solutions

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