1950 AHSME Problems/Problem 13

Revision as of 21:50, 13 November 2011 by Gina (talk | contribs) (Created page with "== Problem== The roots of <math> (x^{2}-3x+2)(x)(x-4)=0 </math> are: <math> \textbf{(A)}\ 4\qquad\textbf{(B)}\ 0\text{ and }4\qquad\textbf{(C)}\ 1\text{ and }2\qquad\textbf{(D)...")
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Problem

The roots of $(x^{2}-3x+2)(x)(x-4)=0$ are:

$\textbf{(A)}\ 4\qquad\textbf{(B)}\ 0\text{ and }4\qquad\textbf{(C)}\ 1\text{ and }2\qquad\textbf{(D)}\ 0,1,2\text{ and }4\qquad\textbf{(E)}\ 1,2\text{ and }4$

Solution

Factor $x^2-3x+2$ to get $(x-2)(x-1).$ The roots are $\boxed{\mathrm{(D)}\ 0,1,2\text{ and }4.}$

See Also

1950 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
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