Difference between revisions of "1950 AHSME Problems/Problem 14"

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==See Also==
 
==See Also==
  
{{AHSME box|year=1950|num-b=13|num-a=15}}
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{{AHSME 50p box|year=1950|num-b=13|num-a=15}}
  
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]

Revision as of 08:32, 29 April 2012

Problem

For the simultaneous equations \[2x-3y=8\\6y-4x=9\]

$\textbf{(A)}\ x=4,y=0\qquad\textbf{(B)}\ x=0,y=\frac{3}{2}\qquad\textbf{(C)}\ x=0,y=0\qquad\\ \textbf{(D)}\ \text{There is no solution}\qquad\textbf{(E)}\ \text{There are an infinite number of solutions}$

Solution

Try to solve this system of equations using the elimination method.

\begin{align*} -2(2x-3y)&=-2(8)\\ 6y-4x&=-16\\ 6y-4x&=9\\ 0&=-7 \end{align*}

Something is clearly contradictory so $\boxed{\mathrm{(D)}\text{ There is no solution}.}$

See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 13
Followed by
Problem 15
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