Difference between revisions of "1950 AHSME Problems/Problem 30"
Mrdavid445 (talk | contribs) (Created page with "==Problem== From a group of boys and girls, <math>15</math> girls leave. There are then left two boys for each girl. After this <math>45</math> boys leave. There are then <math>...") |
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==Problem== | ==Problem== | ||
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From a group of boys and girls, <math>15</math> girls leave. There are then left two boys for each girl. After this <math>45</math> boys leave. There are then <math>5</math> girls for each boy. The number of girls in the beginning was: | From a group of boys and girls, <math>15</math> girls leave. There are then left two boys for each girl. After this <math>45</math> boys leave. There are then <math>5</math> girls for each boy. The number of girls in the beginning was: | ||
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\textbf{(D)}\ 50 \qquad | \textbf{(D)}\ 50 \qquad | ||
\textbf{(E)}\ \text{None of these}</math> | \textbf{(E)}\ \text{None of these}</math> | ||
| + | ==Solution== | ||
| + | {{solution}} | ||
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| + | ==See Also== | ||
| + | {{AHSME box|year=1950|num-b=29|after=Last<br />Question}} | ||
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| + | [[Category:Introductory Algebra Problems]] | ||
Revision as of 14:19, 17 April 2012
Problem
From a group of boys and girls, 
girls leave. There are then left two boys for each girl. After this 
boys leave. There are then 
girls for each boy. The number of girls in the beginning was:
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See Also
| 1950 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 29 |
Followed by Last Question | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
