Difference between revisions of "1950 AHSME Problems/Problem 33"

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\textbf{(D)}\ 36 \qquad
 
\textbf{(D)}\ 36 \qquad
 
\textbf{(E)}\ 36\pi</math>
 
\textbf{(E)}\ 36\pi</math>
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==Solution==
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{{solution}}
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==See Also==
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{{AHSME 50p box|year=1950|num-b=32|num-a=34}}
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[[Category:Introductory Algebra Problems]]
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[[Category:Introductory Geometry Problems]]

Revision as of 08:36, 29 April 2012

Problem

The number of circular pipes with an inside diameter of $1$ inch which will carry the same amount of water as a pipe with an inside diameter of $6$ inches is:

$\textbf{(A)}\ 6\pi \qquad \textbf{(B)}\ 6 \qquad \textbf{(C)}\ 12 \qquad \textbf{(D)}\ 36 \qquad \textbf{(E)}\ 36\pi$

Solution

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See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 32
Followed by
Problem 34
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All AHSME Problems and Solutions