Difference between revisions of "1950 AHSME Problems/Problem 40"
Mrdavid445 (talk | contribs) (Created page with "==Problem== The limit of <math> \frac {x^2\minus{}1}{x\minus{}1}</math> as <math>x</math> approaches <math>1</math> as a limit is: <math>\textbf{(A)}\ 0 \qquad \textbf{(B)}\ \t...") |
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\textbf{(D)}\ 2 \qquad | \textbf{(D)}\ 2 \qquad | ||
\textbf{(E)}\ 1</math> | \textbf{(E)}\ 1</math> | ||
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| + | ==Solution== | ||
| + | {{solution}} | ||
| + | |||
| + | ==See Also== | ||
| + | {{AHSME 50p box|year=1950|num-b=39|num-a=41}} | ||
| + | |||
| + | [[Category:Introductory Algebra Problems]] | ||
Revision as of 08:39, 29 April 2012
Problem
The limit of $\frac {x^2\minus{}1}{x\minus{}1}$ (Error compiling LaTeX. Unknown error_msg) as 
approaches 
as a limit is:
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See Also
| 1950 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 39 |
Followed by Problem 41 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
