Difference between revisions of "1950 AHSME Problems/Problem 48"

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\textbf{(D)}\ \text{One-half the sum of the sides of the triangle} \qquad\\
 
\textbf{(D)}\ \text{One-half the sum of the sides of the triangle} \qquad\\
 
\textbf{(E)}\ \text{Greatest when the point is the center of gravity}</math>
 
\textbf{(E)}\ \text{Greatest when the point is the center of gravity}</math>
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==Solution==
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{{solution}}
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==See Also==
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{{AHSME 50p box|year=1950|num-b=47|num-a=49}}
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[[Category:Introductory Geometry Problems]]

Revision as of 08:42, 29 April 2012

Problem

A point is selected at random inside an equilateral triangle. From this point perpendiculars are dropped to each side. The sum of these perpendiculars is:

$\textbf{(A)}\ \text{Least when the point is the center of gravity of the triangle}\qquad\\ \textbf{(B)}\ \text{Greater than the altitude of the triangle} \qquad\\ \textbf{(C)}\ \text{Equal to the altitude of the triangle}\qquad\\ \textbf{(D)}\ \text{One-half the sum of the sides of the triangle} \qquad\\ \textbf{(E)}\ \text{Greatest when the point is the center of gravity}$

Solution

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See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 47
Followed by
Problem 49
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All AHSME Problems and Solutions