Difference between revisions of "1950 AHSME Problems/Problem 7"

 
Line 3: Line 3:
 
If the digit <math>1</math> is placed after a two digit number whose tens' digit is <math>t</math>, and units' digit is <math>u</math>, the new number is:
 
If the digit <math>1</math> is placed after a two digit number whose tens' digit is <math>t</math>, and units' digit is <math>u</math>, the new number is:
  
<math> \textbf{(A)}\ 10t+u+1\qquad\textbf{(B)}\ 100t+10u+1\qquad\textbf{(C)}\ 100t+10u+1\qquad\textbf{(D)}\ t+u+1\qquad\\ \textbf{(E)}\ \text{None of these answers} </math>
+
<math> \textbf{(A)}\ 10t+u+1\qquad\textbf{(B)}\ 100t+10u+1\qquad\textbf{(C)}\ 1000t+10u+1\qquad\textbf{(D)}\ t+u+1\qquad\\ \textbf{(E)}\ \text{None of these answers} </math>
  
 
==Solution==
 
==Solution==
  
By placing the digit <math>1</math> after a two digit number, you are changing the units place to <math>1</math> and moving everything else up a place. Therefore the answer is <math>\boxed{\textbf{(C)}\ 100t+10u+1}</math>.
+
By placing the digit <math>1</math> after a two digit number, you are changing the units place to <math>1</math> and moving everything else up a place. Therefore the answer is <math>\boxed{\textbf{(B)}\ 100t+10u+1}</math>.
  
 
==See Also==
 
==See Also==

Latest revision as of 20:23, 27 January 2015

Problem

If the digit $1$ is placed after a two digit number whose tens' digit is $t$, and units' digit is $u$, the new number is:

$\textbf{(A)}\ 10t+u+1\qquad\textbf{(B)}\ 100t+10u+1\qquad\textbf{(C)}\ 1000t+10u+1\qquad\textbf{(D)}\ t+u+1\qquad\\ \textbf{(E)}\ \text{None of these answers}$

Solution

By placing the digit $1$ after a two digit number, you are changing the units place to $1$ and moving everything else up a place. Therefore the answer is $\boxed{\textbf{(B)}\ 100t+10u+1}$.

See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Invalid username
Login to AoPS