Difference between revisions of "1953 AHSME Problems/Problem 6"
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== Solution == | == Solution == | ||
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If Charles has <math>5q +1</math> quarters and Richard has <math>q+5</math> quarters, then the difference between them is <math>4q-4</math> quarters. Converting quarters to dimes, the difference between them is <math>\frac{5}{2}\cdot (4)(q-1)</math>, or <math>10(q-1)</math> dimes, <math>\implies \fbox{A}</math> | If Charles has <math>5q +1</math> quarters and Richard has <math>q+5</math> quarters, then the difference between them is <math>4q-4</math> quarters. Converting quarters to dimes, the difference between them is <math>\frac{5}{2}\cdot (4)(q-1)</math>, or <math>10(q-1)</math> dimes, <math>\implies \fbox{A}</math> | ||
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+ | Note that <math>q</math> does not stand for the number of quarters that they have. | ||
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==See Also== | ==See Also== | ||
Latest revision as of 20:34, 1 April 2017
Problem 6
Charles has quarters and Richard has quarters. The difference in their money in dimes is:
Solution
If Charles has quarters and Richard has quarters, then the difference between them is quarters. Converting quarters to dimes, the difference between them is , or dimes,
Note that does not stand for the number of quarters that they have.
See Also
1953 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
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