Difference between revisions of "1959 AHSME Problems/Problem 1"
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==Solution== | ==Solution== | ||
Note that increasing the length of each edge by <math>50</math>% with result in a cube that is similar to the original cube with scale factor <math>1.5</math>. Therefore, the surface area will increase by a factor of <math>1.5^2</math>, or <math>2.25</math>. Converting this back into a percent, the percent increase will be <math>125</math>%. Therefore, the answer is <math>\boxed{\textbf{B}}</math>. | Note that increasing the length of each edge by <math>50</math>% with result in a cube that is similar to the original cube with scale factor <math>1.5</math>. Therefore, the surface area will increase by a factor of <math>1.5^2</math>, or <math>2.25</math>. Converting this back into a percent, the percent increase will be <math>125</math>%. Therefore, the answer is <math>\boxed{\textbf{B}}</math>. | ||
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+ | == See also == | ||
+ | {{AHSME 50p box|year=1959|before=First Question|num-a=2}} | ||
+ | {{MAA Notice}} |
Latest revision as of 21:56, 25 February 2018
Problem 1
Each edge of a cube is increased by %. The percent of increase of the surface area of the cube is:
Solution
Note that increasing the length of each edge by % with result in a cube that is similar to the original cube with scale factor . Therefore, the surface area will increase by a factor of , or . Converting this back into a percent, the percent increase will be %. Therefore, the answer is .
See also
1959 AHSC (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
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All AHSME Problems and Solutions |
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