1959 AHSME Problems/Problem 28
Problem 28
In triangle 
, 
bisects angle 
, and 
bisects angle 
. Points 
and 
are on 
and 
, respectively. The sides of 
are 
, 
, and 
. Then 
where 
is:
Solution
By the angle bisector theorem, 
and 
, so by rearranging the given equation and noting 
and 
, 
.
See also
| 1959 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 27 |
Followed by Problem 29 | |
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