Difference between revisions of "1965 AHSME Problems/Problem 3"
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== Solution == | == Solution == | ||
| − | + | Let us recall <math>\text{PEMDAS}</math>. We calculate the exponent first. <math>(-2)^{-2}=\frac{1}{(-2)^2}=\frac{1}{4}</math> When we substitute, we get <math>81^{\frac{1}{4}}=\sqrt[4]{81}=\boxed{\textbf{(C) }3}</math>. | |
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| + | ~Mathfun1000 | ||
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| + | ==See Also== | ||
| + | {{AHSME box|year=1965|num-b=2|num-a=4}} | ||
| + | {{MAA Notice}} | ||
| + | [[Category:AHSME]][[Category:AHSME Problems]] | ||
Latest revision as of 21:15, 10 January 2023
Problem
The expression 
has the same value as:
Solution
Let us recall 
. We calculate the exponent first. 
When we substitute, we get ![$81^{\frac{1}{4}}=\sqrt[4]{81}=\boxed{\textbf{(C) }3}$](http://latex.artofproblemsolving.com/6/9/e/69eed9e2349acdc080b54330f253506800819b01.png)
.
~Mathfun1000
See Also
| 1965 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
