1968 AHSME Problems/Problem 19

Revision as of 22:36, 9 January 2015 by Vihaar (talk | contribs) (See also)

Problem

Let $n$ be the number of ways $10$ dollars can be changed into dimes and quarters, with at least one of each coin being used. Then $n$ equals:

$\text{(A) } 40\quad \text{(B) } 38\quad \text{(C) } 21\quad \text{(D) } 20\quad \text{(E) } 19$

Solution

$\fbox{E}$

See also

1968 AHSME (ProblemsAnswer KeyResources)
Preceded by
[[1968 AHSME Problems/Problem {{{num-b}}}|Problem {{{num-b}}}]]
Followed by
[[1968 AHSME Problems/Problem {{{num-a}}}|Problem {{{num-a}}}]]
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png