Difference between revisions of "1968 AHSME Problems/Problem 3"

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== Solution ==
 
== Solution ==
<math>\fbox{}</math>
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== See also ==
 
== See also ==
{{AHSME box|year=1968|num-b=2|num-a=4}}   
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{{AHSME 35p box|year=1968|num-b=2|num-a=4}}   
  
 
[[Category: Introductory Algebra Problems]]
 
[[Category: Introductory Algebra Problems]]
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 01:52, 16 August 2023

Problem

A straight line passing through the point $(0,4)$ is perpendicular to the line $x-3y-7=0$. Its equation is:

$\text{(A) } y+3x-4=0\quad \text{(B) } y+3x+4=0\quad \text{(C) } y-3x-4=0\quad \\ \text{(D) } 3y+x-12=0\quad \text{(E) } 3y-x-12=0$

Solution

$\fbox{A}$

See also

1968 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35
All AHSME Problems and Solutions

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