Difference between revisions of "1968 AHSME Problems/Problem 8"

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== See also ==
 
== See also ==
{{AHSME box|year=1968|num-b=7|num-a=9}}   
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{{AHSME 35p box|year=1968|num-b=7|num-a=9}}   
  
 
[[Category: Introductory Algebra Problems]]
 
[[Category: Introductory Algebra Problems]]
 
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{{MAA Notice}}

Latest revision as of 01:52, 16 August 2023

Problem

A positive number is mistakenly divided by $6$ instead of being multiplied by $6.$ Based on the correct answer, the error thus committed, to the nearest percent, is :

$\text{(A) } 100\quad \text{(B) } 97\quad \text{(C) } 83\quad \text{(D) } 17\quad \text{(E) } 3$

Solution

$\fbox{B}$

See also

1968 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35
All AHSME Problems and Solutions

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