1979 AHSME Problems/Problem 16
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Problem 16
A circle with area is contained in the interior of a larger circle with area . If the radius of the larger circle is , and if is an arithmetic progression, then the radius of the smaller circle is
Solution
Solution by e_power_pi_times_i
The area of the larger circle is . Then are in an arithmetic progression. Thus . This simplifies to , or . The radius of the smaller circle is .
See also
1979 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
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