Difference between revisions of "1986 AHSME Problems/Problem 11"
Cocohearts (talk | contribs) m (→Problem) |
(→Problem) |
||
Line 1: | Line 1: | ||
− | == | + | ==Problem== |
In <math>\triangle ABC, AB = 13, BC = 14</math> and <math>CA = 15</math>. Also, <math>M</math> is the midpoint of side <math>AB</math> and <math>H</math> is the foot of the altitude from <math>A</math> to <math>BC</math>. | In <math>\triangle ABC, AB = 13, BC = 14</math> and <math>CA = 15</math>. Also, <math>M</math> is the midpoint of side <math>AB</math> and <math>H</math> is the foot of the altitude from <math>A</math> to <math>BC</math>. |
Latest revision as of 15:21, 5 June 2020
Problem
In and . Also, is the midpoint of side and is the foot of the altitude from to . The length of is
Solution
In a right triangle, the length of the hypotenuse is twice the length of the median which bisects it. If the hypotenuse is , the median must be .
See also
1986 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.