1986 AHSME Problems/Problem 22
Problem
Six distinct integers are picked at random from . What is the probability that, among those selected, the second smallest is ?
Solution
The total number of ways to choose 6 numbers is
Assume 3 is the SECOND lowest number. There are 5 numbers left to choose, 4 of which must be greater than 3 and 1 which must be less than 3. This is equivalent to choosing 4 numbers from the 7 numbers larger than 3, and 1 number from the 2 numbers less than 3.
Thus,
See also
1986 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 21 |
Followed by Problem 23 | |
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