Difference between revisions of "1990 AIME Problems/Problem 4"
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== Problem == | == Problem == | ||
| + | Find the positive solution to | ||
| + | <center><math>\frac 1{x^2-10x-29}+\frac1{x^2-10x-45}-\frac 2{x^2-10x-69}=0</math></center> | ||
== Solution == | == Solution == | ||
{{solution}} | {{solution}} | ||
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== See also == | == See also == | ||
| − | + | {{AIME box|year=1990|num-b=3|num-a=5}} | |
Revision as of 01:21, 2 March 2007
Problem
Find the positive solution to
Solution
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See also
| 1990 AIME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
