Difference between revisions of "1998 AJHSME Problems/Problem 11"

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Harry has 3 sisters and 5 brothers. His sister, being a girl, would have 1 less sister and 1 more brother.
 
Harry has 3 sisters and 5 brothers. His sister, being a girl, would have 1 less sister and 1 more brother.
  
<math>3-1=2</math>
+
<math>S = 3-1=2 </math>
<math>5+1=6</math>
 
  
<math>2\times6=12=\boxed{C}</math>
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<math>B = 5+1=6</math>
  
 +
<math>S\cdot B = 2\times6=12=\boxed{C}</math>
  
 
== See also ==
 
== See also ==

Revision as of 11:16, 31 July 2011

Problem 11

Harry has 3 sisters and 5 brothers. His sister Harriet has $\text{S}$ sisters and $\text{B}$ brothers. What is the product of $\text{S}$ and $\text{B}$?

$\text{(A)}\ 8 \qquad \text{(B)}\ 10 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 15 \qquad \text{(E)}\ 18$

Solution

Harry has 3 sisters and 5 brothers. His sister, being a girl, would have 1 less sister and 1 more brother.

$S = 3-1=2$

$B = 5+1=6$

$S\cdot B = 2\times6=12=\boxed{C}$

See also

1998 AJHSME (ProblemsAnswer KeyResources)
Preceded by
1997 AJHSME
Followed by
1999 AMC 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions