Difference between revisions of "1998 AJHSME Problems/Problem 11"

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==Problem 11==
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==Problem==
  
 
Harry has 3 sisters and 5 brothers.  His sister Harriet has <math>\text{S}</math> sisters and <math>\text{B}</math> brothers.  What is the product of <math>\text{S}</math> and <math>\text{B}</math>?
 
Harry has 3 sisters and 5 brothers.  His sister Harriet has <math>\text{S}</math> sisters and <math>\text{B}</math> brothers.  What is the product of <math>\text{S}</math> and <math>\text{B}</math>?

Revision as of 12:50, 23 December 2012

Problem

Harry has 3 sisters and 5 brothers. His sister Harriet has $\text{S}$ sisters and $\text{B}$ brothers. What is the product of $\text{S}$ and $\text{B}$?

$\text{(A)}\ 8 \qquad \text{(B)}\ 10 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 15 \qquad \text{(E)}\ 18$

Solution

Harry has 3 sisters and 5 brothers. His sister, being a girl, would have 1 less sister and 1 more brother.

$S = 3-1=2$

$B = 5+1=6$

$S\cdot B = 2\times6=12=\boxed{C}$

See also

1998 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 10
Followed by
Problem 12
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions