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2003 AMC 12B Problems/Problem 1

Revision as of 09:06, 5 February 2008 by 1=2 (talk | contribs) (See also)

Problem

Which of the following is the same as

\[\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}\]?

$\text {(A) } -1 \qquad \text {(B) } -\frac{2}{3} \qquad \text {(C) } \frac{2}{3} \qquad \text {(D) } 1 \qquad \text {(E) } \frac{14}{3}$

Solution

$2-4+6-8+10-12+14=-2-2-2+14=8$


$3-6+9-12+15-18+21=-3-3-3+21=12$


$\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}=\frac{8}{12}=\frac{2}{3} \Rightarrow \text {(C)}$

See also

2003 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
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All AMC 12 Problems and Solutions
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