Difference between revisions of "2003 AMC 12B Problems/Problem 9"
m (→Solution) |
|||
| Line 11: | Line 11: | ||
<cmath>m = \frac{f(6) - f(2)}{\Delta x} = \frac{12}{6 - 2} = 3</cmath> | <cmath>m = \frac{f(6) - f(2)}{\Delta x} = \frac{12}{6 - 2} = 3</cmath> | ||
| − | <cmath>f(12) - f(2) = m \Delta x = | + | <cmath>f(12) - f(2) = m \Delta x = 3(12 - 2) = 30 \Rightarrow \text (D)</cmath> |
==See Also== | ==See Also== | ||
{{AMC12 box|year=2003|ab=B|num-b=8|num-a=10}} | {{AMC12 box|year=2003|ab=B|num-b=8|num-a=10}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 19:54, 26 September 2017
Problem
Let 
be a linear function for which 
What is 
Solution
Since is a linear function with slope 
,
![\[m = \frac{f(6) - f(2)}{\Delta x} = \frac{12}{6 - 2} = 3\]](http://latex.artofproblemsolving.com/a/a/2/aa203aedcd175b965d80f840ac73c7f9356e3456.png)
![\[f(12) - f(2) = m \Delta x = 3(12 - 2) = 30 \Rightarrow \text (D)\]](http://latex.artofproblemsolving.com/1/f/d/1fd57e2924ffbf1a5fdb30a0312b68a900db6039.png)
See Also
| 2003 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 8 |
Followed by Problem 10 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
