Difference between revisions of "2003 AMC 12B Problems/Problem 9"

Line 1: Line 1:
== Problem 9 ==
+
== Problem ==
 
Let <math>f</math> be a linear function for which <math>f(6) - f(2) = 12.</math> What is <math>f(12) - f(2)?</math>
 
Let <math>f</math> be a linear function for which <math>f(6) - f(2) = 12.</math> What is <math>f(12) - f(2)?</math>
  
Line 6: Line 6:
 
</math>
 
</math>
  
 
+
==Solution==
[[2003 AMC 12B Problems/Problem 9|Solution]]
 
 
 
 
Since <math>f</math> is a linear function with slope <math>m</math>,
 
Since <math>f</math> is a linear function with slope <math>m</math>,
  
Line 14: Line 12:
  
 
<cmath>f(12) - f(2) = m \Delta x = 4(12 - 2) = 30 \Rightarrow \text (D)</cmath>
 
<cmath>f(12) - f(2) = m \Delta x = 4(12 - 2) = 30 \Rightarrow \text (D)</cmath>
 +
 +
==See Also==
 +
{{AMC12 box|year=2003|ab=B|num-b=8|num-a=10}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 00:37, 5 January 2014

Problem

Let $f$ be a linear function for which $f(6) - f(2) = 12.$ What is $f(12) - f(2)?$

$\text {(A) } 12 \qquad \text {(B) } 18 \qquad \text {(C) } 24 \qquad \text {(D) } 30 \qquad \text {(E) } 36$

Solution

Since $f$ is a linear function with slope $m$,

\[m = \frac{f(6) - f(2)}{\Delta x} = \frac{12}{6 - 2} = 3\]

\[f(12) - f(2) = m \Delta x = 4(12 - 2) = 30 \Rightarrow \text (D)\]

See Also

2003 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png