Difference between revisions of "2005 AMC 8 Problems/Problem 17"

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(Undo revision 80383 by Bz1 (talk))
 
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==Solution==
 
==Solution==
 
Average speed is distance over time, or the slope of the line through the point and the origin. <math>\boxed{\textbf{(E)}\ \text{Evelyn}}</math> has the steepest line, and runs the greatest distance for the shortest amount of time.
 
Average speed is distance over time, or the slope of the line through the point and the origin. <math>\boxed{\textbf{(E)}\ \text{Evelyn}}</math> has the steepest line, and runs the greatest distance for the shortest amount of time.
When activated, a prismarine block will be shoot out in the direction pointed. The block will begin to continuously throw Treasure Shards around it in a circle for 30 seconds.
 
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2005|num-b=16|num-a=18}}
 
{{AMC8 box|year=2005|num-b=16|num-a=18}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 17:34, 24 September 2016

Problem

The results of a cross-country team's training run are graphed below. Which student has the greatest average speed? [asy] for ( int i = 1; i <= 7; ++i ) {     draw((i,0)--(i,6)); }  for ( int i = 1; i <= 5; ++i ) {     draw((0,i)--(8,i)); } draw((-0.5,0)--(8,0), linewidth(1)); draw((0,-0.5)--(0,6), linewidth(1)); label("$O$", (0,0), SW); label(scale(.85)*rotate(90)*"distance", (0, 3), W); label(scale(.85)*"time", (4, 0), S); dot((1.25, 4.5)); label(scale(.85)*"Evelyn", (1.25, 4.8), N); dot((2.5, 2.2)); label(scale(.85)*"Briana", (2.5, 2.2), S); dot((4.25,5.2)); label(scale(.85)*"Carla", (4.25, 5.2), SE); dot((5.6, 2.8)); label(scale(.85)*"Debra", (5.6, 2.8), N); dot((6.8, 1.4)); label(scale(.85)*"Angela", (6.8, 1.4), E); [/asy]

$\textbf{(A)}\ \text{Angela}\qquad\textbf{(B)}\ \text{Briana}\qquad\textbf{(C)}\ \text{Carla}\qquad\textbf{(D)}\ \text{Debra}\qquad\textbf{(E)}\ \text{Evelyn}$

Solution

Average speed is distance over time, or the slope of the line through the point and the origin. $\boxed{\textbf{(E)}\ \text{Evelyn}}$ has the steepest line, and runs the greatest distance for the shortest amount of time.

See Also

2005 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 16
Followed by
Problem 18
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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