Difference between revisions of "2006 Cyprus MO/Lyceum/Problem 17"
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− | <math>AB\Gamma</math> is [[equilateral triangle]] of side <math>\alpha</math> and <math> | + | <math>AB\Gamma</math> is [[equilateral triangle]] of side <math>\alpha</math> and <math>A\Delta=BE=\frac{\alpha}{3}</math>. The measure of the angle <math>\ang \Gamma PE</math> is |
A. <math>60^{\circ}</math> | A. <math>60^{\circ}</math> |
Revision as of 21:59, 17 October 2007
Problem
is equilateral triangle of side and . The measure of the angle $\ang \Gamma PE$ (Error compiling LaTeX. ! Undefined control sequence.) is
A.
B.
C.
D.
E.
Solution
Draw a segment such that . By symmetry we see the triangle in the middle is equilateral, so the measure of $\ang CPE = 60^{\circ} \ \mathrm{(A)}$ (Error compiling LaTeX. ! Undefined control sequence.).
See also
2006 Cyprus MO, Lyceum (Problems) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 |