# Difference between revisions of "2007 UNCO Math Contest II Problems/Problem 2"

## Problem

In Grants Pass, Oregon $\frac{4}{5}$ of the men are married to $\frac{3}{7}$ of the women. What fraction of the adult population is married? Give a possible generalization.

## Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

Let the number of men be equal to $m$ and the number of women be equal to $w$, where $m$ and $w$ are whole numbers. Assuming a marriage consists of one man and one woman, we see that the number of married men is equal to the number of married women in the equation:

$\frac{4}{5}\times m = \frac{3}{7}\times w$

$w = \frac{28}{15} m$

Dividing the the number of married persons by the entire adult population gives us:

$%_{married} = \frac{\frac{3}{7}w\times\frac{4}{5}m}{m + w}$ (Error compiling LaTeX. ! Missing $inserted.)$%_{married} = \frac{\frac{8}{5}m}{{43}{15}m}$(Error compiling LaTeX. ! Missing$ inserted.)

$%_{married} = \frac{24}{43} ~ 55.8%$ (Error compiling LaTeX. ! Missing \$ inserted.)

## See Also

 2007 UNCO Math Contest II (Problems • Answer Key • Resources) Preceded byProblem 1 Followed byProblem 3 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 All UNCO Math Contest Problems and Solutions
Invalid username
Login to AoPS