Difference between revisions of "2008 AMC 10B Problems/Problem 22"

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==Problem==
 
==Problem==
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Three red beads, two white beads, and one blue bead are placed in line in random order. What is the probability that no two neighboring beads are the same color?
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A) 1/12 B) 1/10 C) 1/6 D) 1/3 E) 1/2
  
 
==Solution==
 
==Solution==
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C) 1/6
  
 
==See also==
 
==See also==
 
{{AMC10 box|year=2008|ab=B|num-b=21|num-a=23}}
 
{{AMC10 box|year=2008|ab=B|num-b=21|num-a=23}}

Revision as of 11:13, 4 January 2009

Problem

Three red beads, two white beads, and one blue bead are placed in line in random order. What is the probability that no two neighboring beads are the same color?

A) 1/12 B) 1/10 C) 1/6 D) 1/3 E) 1/2

Solution

C) 1/6

See also

2008 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 21
Followed by
Problem 23
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions
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