Difference between revisions of "2009 AMC 10A Problems/Problem 1"
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== Solution 2 == | == Solution 2 == | ||
− | We want to find <math>\left\ | + | We want to find <math>\left\lceiling\frac{128}{12}\right\rceiling</math> because there are a whole number of cans. |
<math>\frac{128}{12} = 10R8\longrightarrow 11\longrightarrow \fbox{E}.</math> | <math>\frac{128}{12} = 10R8\longrightarrow 11\longrightarrow \fbox{E}.</math> |
Revision as of 07:43, 6 May 2018
Problem
One can, can hold ounces of soda, what is the minimum number of cans needed to provide a gallon ( ounces) of soda?
Solution 1
cans would hold ounces, but , so cans are required. Thus, the answer is .
Solution 2
We want to find $\left\lceiling\frac{128}{12}\right\rceiling$ (Error compiling LaTeX. ! Undefined control sequence.) because there are a whole number of cans.
2009 AMC 10A (Problems • Answer Key • Resources) | ||
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All AMC 10 Problems and Solutions |
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