2010 AMC 12B Problems/Problem 9

Revision as of 17:17, 12 July 2010 by Lg5293 (talk | contribs) (Created page with '== Problem 9 == Let <math>n</math> be the smallest positive integer such that <math>n</math> id divisible by <math>20</math>, <math>n^2</math> is a perfect cube, and <math>n^3</m…')
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem 9

Let $n$ be the smallest positive integer such that $n$ id divisible by $20$, $n^2$ is a perfect cube, and $n^3$ is a perfect square. What is the number of digits of $n$?

$\textbf{(A)}\ 3 \qquad \textbf{(B)}\ 4 \qquad \textbf{(C)}\ 5 \qquad \textbf{(D)}\ 6 \qquad \textbf{(E)}\ 7$

Solution

See also

2010 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions