Difference between revisions of "2010 AMC 8 Problems/Problem 6"
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− | + | ==Problem== | |
− | + | Which of the following figures has the greatest number of lines of symmetry? | |
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+ | <math> \textbf{(A)}\ \text{equilateral triangle} </math> | ||
− | Therefore, the answer is <math> \textbf{(E)}\ \text{square} </math>. | + | <math> \textbf{(B)}\ \text{non-square rhombus} </math> |
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+ | <math> \textbf{(C)}\ \text{non-square rectangle} </math> | ||
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+ | <math> \textbf{(D)}\ \text{isosceles trapezoid} </math> | ||
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+ | <math> \textbf{(E)}\ \text{square} </math> | ||
+ | |||
+ | ==Solution== | ||
+ | An equilateral triangle has <math>3</math> lines of symmetry. | ||
+ | A non-square rhombus has <math>2</math> lines of symmetry. | ||
+ | A non-square rectangle has <math>2</math> lines of symmetry. | ||
+ | An isosceles trapezoid has <math>1</math> line of symmetry. | ||
+ | A square has <math>4</math> lines of symmetry. | ||
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+ | |||
+ | Therefore, the answer is <math>\boxed{ \textbf{(E)}\ \text{square} }</math>. | ||
==See Also== | ==See Also== | ||
− | {{AMC8 box|year=2010|num-b= | + | {{AMC8 box|year=2010|num-b=5|num-a=7}} |
+ | {{MAA Notice}} |
Revision as of 18:12, 6 January 2018
Problem
Which of the following figures has the greatest number of lines of symmetry?
Solution
An equilateral triangle has lines of symmetry. A non-square rhombus has lines of symmetry. A non-square rectangle has lines of symmetry. An isosceles trapezoid has line of symmetry. A square has lines of symmetry.
Therefore, the answer is .
See Also
2010 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.