Difference between revisions of "2010 AMC 8 Problems/Problem 6"

m (Solution)
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==Solution==
 
==Solution==
An equilateral triangle has 3 lines of symmetry.
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An equilateral triangle has <math>3</math> lines of symmetry.
A non-square rhombus has 2 lines of symmetry.
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A non-square rhombus has <math>2</math> lines of symmetry.
A non-square rectangle has 2 lines of symmetry.
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A non-square rectangle has <math>2</math> lines of symmetry.
An isosceles trapezoid has 1 line of symmetry.
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An isosceles trapezoid has <math>1</math> line of symmetry.
A square has 4 lines of symmetry.
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A square has <math>4</math> lines of symmetry.
  
  

Latest revision as of 18:12, 6 January 2018

Problem

Which of the following figures has the greatest number of lines of symmetry?

$\textbf{(A)}\ \text{equilateral triangle}$

$\textbf{(B)}\ \text{non-square rhombus}$

$\textbf{(C)}\ \text{non-square rectangle}$

$\textbf{(D)}\ \text{isosceles trapezoid}$

$\textbf{(E)}\ \text{square}$

Solution

An equilateral triangle has $3$ lines of symmetry. A non-square rhombus has $2$ lines of symmetry. A non-square rectangle has $2$ lines of symmetry. An isosceles trapezoid has $1$ line of symmetry. A square has $4$ lines of symmetry.


Therefore, the answer is $\boxed{ \textbf{(E)}\ \text{square} }$.

See Also

2010 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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