Difference between revisions of "2011 AMC 12B Problems/Problem 23"
(→Solution) |
(→Solution) |
||
Line 6: | Line 6: | ||
==Solution== | ==Solution== | ||
− | We declare a point <math>(x, y)</math> to make up for the extra steps that the bug has to move. If the point <math>(x, y)</math> satisfies the property that <math>|x - 3| + |y + 2| + |x + 3| + |y - 2| \le 20</math>, then it is in the desirable range because <math>|x - 3| + |y + 2|</math> is the length of the shortest path from <math>(x,y)</math> to <math>(3, -2)</math> | + | We declare a point <math>(x, y)</math> to make up for the extra steps that the bug has to move. If the point <math>(x, y)</math> satisfies the property that <math>|x - 3| + |y + 2| + |x + 3| + |y - 2| \le 20</math>, then it is in the desirable range because <math>|x - 3| + |y + 2|</math> is the length of the shortest path from <math>(x,y)</math> to <math>(3, -2)</math> and <math>|x + 3| + |y - 2|</math> is the length of the shortest path from <math>(x,y)</math> to <math>(-3, 2)</math> |
Revision as of 23:11, 19 January 2020
Problem
A bug travels in the coordinate plane, moving only along the lines that are parallel to the -axis or -axis. Let and . Consider all possible paths of the bug from to of length at most . How many points with integer coordinates lie on at least one of these paths?
Solution
We declare a point to make up for the extra steps that the bug has to move. If the point satisfies the property that , then it is in the desirable range because is the length of the shortest path from to and is the length of the shortest path from to
If , then satisfy the property. there are lattice points here.
else let (and for because it is symmetrical) We set 8 as the upper bound for x because the shortest distance from to added to the shortest distance from to is . Since the minimum value for the difference between the y-coordinates is at , we get or . Thus, the upper and lower bounds for are and , respectively.
Now we test each value for x satisfying and double the result because of symmetry.
For , there are lattice points,
for , there are lattice points,
for , there are lattice points,
for , there are lattice points,
For , there are lattice points.
Hence, there are a total of lattice points.
One may also obtain the result by using Pick's Theorem(how?).
See also
2011 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 22 |
Followed by Problem 24 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.