Difference between revisions of "2013 AMC 10B Problems/Problem 2"

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Since each step is <math>2</math> feet, his garden is <math>30</math> by <math>40</math> feet.  Thus, the area of <math>30(40) = 1200</math> square feet.  Since he is expecting <math>\frac{1}{2}</math> of a pound per square foot, the total amount of potatoes expected is <math>1200 \times \frac{1}{2} =  \boxed{\textbf{(A) }600}</math>
 
Since each step is <math>2</math> feet, his garden is <math>30</math> by <math>40</math> feet.  Thus, the area of <math>30(40) = 1200</math> square feet.  Since he is expecting <math>\frac{1}{2}</math> of a pound per square foot, the total amount of potatoes expected is <math>1200 \times \frac{1}{2} =  \boxed{\textbf{(A) }600}</math>
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== See also ==
 +
{{AMC10 box|year=2013|ab=B|num-b=1|num-a=3}}

Revision as of 16:57, 27 March 2013

Problem

Mr. Green measures his rectangular garden by walking two of the sides and finding that it is $15$ steps by $20$ steps. Each of Mr. Green's steps is $2$ feet long. Mr. Green expects a half a pound of potatoes per square foot from his garden. How many pounds of potatoes does Mr. Green expect from his garden?

$\textbf{(A)}\ 600 \qquad\textbf{(B)}\ 800  \qquad\textbf{(C)}\ 1000 \qquad\textbf{(D)}\ 1200 \qquad\textbf{(E)}\ 1400$

Solution

Since each step is $2$ feet, his garden is $30$ by $40$ feet. Thus, the area of $30(40) = 1200$ square feet. Since he is expecting $\frac{1}{2}$ of a pound per square foot, the total amount of potatoes expected is $1200 \times \frac{1}{2} =  \boxed{\textbf{(A) }600}$

See also

2013 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AMC 10 Problems and Solutions
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