Difference between revisions of "2014 AMC 8 Problems"

(Problem 25)
(Problem 25)
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[[2014 AMC 8 Problems/Problem 24|Solution]]
 
[[2014 AMC 8 Problems/Problem 24|Solution]]
  
==Problem 25==
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==Problem 25=
  
 
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<math>[asy]
[[2014 AMC 8 Problems/Problem 25|Solution]]
 
{{MAA Notice}}
 
 
 
[asy]
 
 
size(10cm); pathpen=black; pointpen=black;
 
size(10cm); pathpen=black; pointpen=black;
 
D(arc((-2,0),1,300,360));
 
D(arc((-2,0),1,300,360));
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D((-1.5,1)--(5.5,1));
 
D((-1.5,1)--(5.5,1));
 
D((-1.5,0)--(5.5,0),dashed);
 
D((-1.5,0)--(5.5,0),dashed);
D((-1.5,-1)--(5.5,-1));[/asy]
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D((-1.5,-1)--(5.5,-1));[/asy]</math>
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 +
 
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[[2014 AMC 8 Problems/Problem 25|Solution]]
 +
{{MAA Notice}}

Revision as of 22:28, 26 November 2014

Problem 1

Harry and Terry are each told to calculate $8-(2+5)$. Harry gets the correct answer. Terry ignores the parentheses and calculates $8-2+5$. If Harry's answer is $H$ and Terry's answer is $T$, what is $H-T$?

$\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad\textbf{(E) }10$

Solution

Problem 2

Solution

Problem 3

Solution

Problem 4

Solution

Problem 5

Solution

Problem 6

Solution

Problem 7

Solution

Problem 8

Solution

Problem 9

Solution

Problem 10

Solution

Problem 11

Solution

Problem 12

Solution

Problem 13

Solution

Problem 14

Solution

Problem 15

Solution

Problem 16

Solution

Problem 17

Solution

Problem 18

Solution

Problem 19

Solution

Problem 20

Solution

Problem 21

Solution

Problem 22

Solution

Problem 23

Solution

Problem 24

Solution

=Problem 25

$[asy] size(10cm); pathpen=black; pointpen=black; D(arc((-2,0),1,300,360)); D(arc((0,0),1,0,180)); D(arc((2,0),1,180,360)); D(arc((4,0),1,0,180)); D(arc((6,0),1,180,240)); D((-1.5,1)--(5.5,1)); D((-1.5,0)--(5.5,0),dashed); D((-1.5,-1)--(5.5,-1));[/asy]$ (Error compiling LaTeX. ! Missing $ inserted.)


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