Difference between revisions of "2014 AMC 8 Problems/Problem 1"
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+ | ==Problem== | ||
+ | Harry and Terry are each told to calculate <math>8-(2+5)</math>. Harry gets the correct answer. Terry ignores the parentheses and calculates <math>8-2+5</math>. If Harry's answer is <math>H</math> and Terry’s answer is <math>T</math>, what is <math>H-T</math>? | ||
− | + | <math>\textbf{(A) }-10\qquad\textbf{(B) }-6\qquad\textbf{(C) }0\qquad\textbf{(D) }6\qquad \textbf{(E) }10</math> | |
− | \textbf{(A) }-10 | + | ==Solution== |
+ | We have <math>H=8-7=1</math> and <math>T=8-2+5=11</math>. Clearly <math>1-11=-10</math> | ||
+ | , so our answer is <math>\boxed{\textbf{(A)}-10}</math>. | ||
+ | |||
+ | ==See Also== | ||
+ | {{AMC8 box|year=2014|before=First Problem|num-a=2}} | ||
+ | {{MAA Notice}} |
Latest revision as of 15:01, 11 June 2021
Problem
Harry and Terry are each told to calculate . Harry gets the correct answer. Terry ignores the parentheses and calculates . If Harry's answer is and Terry’s answer is , what is ?
Solution
We have and . Clearly , so our answer is .
See Also
2014 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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