2014 AMC 8 Problems/Problem 1

Revision as of 20:56, 10 November 2019 by Nehnrh (talk | contribs) (Problem)

RIchard is phat

Solution

We have $H=8-7=1$ and $T=8-2+5=11$. Clearly $1-11=-10$ , so our answer is $\boxed{\textbf{(A)}-10}$.

See Also

2014 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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