2014 AMC 8 Problems/Problem 18

Revision as of 20:40, 26 November 2014 by Mathonator (talk | contribs)

Problem

Four children were born at City Hospital yesterday. Assume each child is equally likely to be a boy or a girl. Which of the following outcomes is most likely

$\textbf{(A) }$ all $4$ are boys $\qquad\textbf{(B) }$ all $4$ are girls $\qquad\textbf{(C) }$ $2$ are girls and $2$ are boys $\qquad\textbf{(D) }$ $3$ are of one gender and $1$ is of the other gender $\qquad\textbf{(E) }$ all of these outcomes are equally likely

See Also

2014 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 17
Followed by
Problem 19
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Invalid username
Login to AoPS